An organ pipe, open from both end produces 5 beats per second when vibrated with a source of frequency 200 Hz. The second harmonic of the same pipes produces 10 beats per second with a source of frequency 420 Hz. The frequency of source is
Text Solution
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Initially number of beats per second = 5
∴ ∴ Frequency of pipe = 200 ± ± 5 = 195 Hz or 205 Hz ...(i)
Frequency of second harmonics of the pipe = 2n and number of beats in this case = 10
∴ ∴ 2n = 420 ± ± 10 ⇒ ⇒ 410 Hz or 430 Hz
⇒ ⇒ n = 205 Hz or 215 H ... (ii)
From equation (i) and (ii) it is clear that n = 205 Hz
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